Thermofluids question, saturated water, piston-cylinder.

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Homework Statement


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Hi, not sure if I posted this in the correct section... I have a solution, but am unsure if I am correct in going about it. The answer is not given, so I am having trouble figuring if I'm right or not.

Anyway, the question goes like this.

Saturated water mixture initially in a piston-cylinder device with a stopper.

Initial state: Volume, V1 = 0.00078539 m^3
Quality, x = 0.85
Pressure, P1 = 125 kPa

Heat is then introduced, after which the piston hits the stopper. The heating is continued until the pressure reaches 200 kPa.

Final state: Volume, V2 = 2Vi = 0.00157079
Pressure, P2 = 200 kPa

a) Find the initial temperature and mass of the liquid.

b) How is the final state, and what is its temperature?

The Attempt at a Solution


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a) I used the provided saturated water table, to find Tsat for P = 125 kPa, and got 105.97C.

For the mass of the liquid, I used x = (v1 - vf) / (vg - vf), where required values are retrieved from the table.

which gave v1 = 1.1689 m^3/kg

Mass of entire mixture, mt = V1/v1 = 0.00067191 kg

x = (mt - mL) / mt

mL = 0.00010078 kg

b) For the final state, I checked the saturated table for P = 200 kPa and found that the specific volume of the substance in question is more than that of saturated vapor at 200 kPa, so using that logic I deduced the final state to be superheated vapor.

v2 = V2 / mt

The temperature is then interpolated from the superheated vapor table at 200 kPa using the specific volume.

It was about 740 degrees celsius.

** Additional thought

Also, if the question required me to think about the state just as the piston hits the stopper, do I use P = 125 kPa, to find the specific volume and compare it with that in the saturated water table? So if v > v of gas --> superheated vapor?
 
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