Thermos Coffee Cooling: What is the Final Temperature?

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SUMMARY

The discussion focuses on calculating the final temperature of coffee in a thermos after adding two 11g ice cubes at 0°C. The initial temperature of the coffee is 85°C, and the relevant equations include Qf = mLfusion and Q = mcΔT. The key conclusion is that the final temperature will be the same for both the coffee and melted ice, as they reach thermal equilibrium. The total heat transfer is zero, allowing for the establishment of a balanced equation to solve for the final temperature.

PREREQUISITES
  • Understanding of heat transfer principles
  • Familiarity with the concept of thermal equilibrium
  • Knowledge of specific heat capacity and latent heat
  • Ability to apply the equations Qf = mLfusion and Q = mcΔT
NEXT STEPS
  • Study the concept of thermal equilibrium in detail
  • Learn about specific heat capacity calculations for different substances
  • Explore latent heat and its applications in phase changes
  • Practice solving problems involving heat transfer and energy conservation
USEFUL FOR

Students studying thermodynamics, physics educators, and anyone interested in understanding heat transfer in practical scenarios.

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Homework Statement


A thermos contains 150 cm3 of coffee at 85 oC. To cool the coffee, you drop two 11g ice cubes into the thermos. The ice cubesare initially at 0 oC
and melt completely. What is the final temperature of the coffee? (Treat the coffee as if it were water)



Homework Equations


Qf = mLfusion
Q = mcΔT

The Attempt at a Solution



I am trying to help someone with this problem. They have yet to learn about internal energy, so I am a little lost (forgetful) as to how to approach this problem
and explain it so that it makes sense.



How would you approach this problem?

Thanks,
Casey
 
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I know that the final temps of coffee and ice will be the same since they reach equilibrium. I also know that there should (probably) be 3 terms: Q of the coffee, Q of the ice melting, and Q of the melt-water changing temp.

But I cannot figure out out to set up a balanced equation...
 
I got it...Total heat transfer with environment = 0...piece of cake...
 

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