Can't the trick (finding final temperature)

In summary, the question involves a Thermos with 130 cm3 of hot coffee at 80.0 degrees C and a 12.0 g ice cube at its melting point being added to cool the coffee. The task is to determine the decrease in temperature of the coffee once the ice has melted, assuming the coffee is pure water and there are no energy exchanges with the environment. The relevant equations are the specific heat of water, the latent heat of fusion, and the density of water. The solution involves finding the sum of all heats in the system and setting it equal to zero, as well as recognizing that the heat lost by the coffee is equal to the heat gained by the ice.
  • #1
nabilsaleh
14
0

Homework Statement



An insulated Thermos contains 130 cm3 of hot coffeeat 80.0 degrees C. You put in a 12.0 g ice cube at its meltingpoint to cool the coffee. By how many degrees has your coffeecooled once the ice has melted? Treat the coffee as though it werepure water and neglect energy exchanges with the environment.


Homework Equations



The specific heat of water is 4186 J/kg·K. The latent heat of fusion is 333 kJ/kg. The density of water is 1.00 g/cm3.



The Attempt at a Solution




I know the way to solve it but there is a little bug that's cuzing me to go off track and end up getting a wrong answer! I've tried solving this question at least 13 times now. I know that sum of all Heats in the system is equal to zero because it's kinda isolated system. And i know that the heat lost by coffee is equal to the heat gained by the ice!
 
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  • #2
Show your work, please.

ehild
 

1. Can you explain the "trick" for finding the final temperature in a scientific experiment?

The "trick" for finding the final temperature in a scientific experiment is to use the principle of thermal equilibrium. This means that when two objects with different temperatures come into contact with each other, heat will flow from the warmer object to the cooler one until they reach the same temperature. By using this principle, we can calculate the final temperature of the two objects.

2. How do you account for different thermal properties of the objects in the final temperature calculation?

When calculating the final temperature, we must take into account the thermal properties of the objects such as their specific heat capacities and thermal conductivities. These properties determine how much heat energy is required to raise the temperature of an object and how quickly it can transfer heat to another object. By using these values in our calculation, we can accurately determine the final temperature.

3. Is the "trick" for finding final temperature applicable to all types of materials?

Yes, the "trick" for finding final temperature is applicable to all types of materials as long as they are in thermal contact with each other. This principle is a fundamental concept in thermodynamics and applies to all types of matter, from solids to liquids and gases.

4. Are there any limitations to using the "trick" for finding final temperature?

One limitation of using the "trick" for finding final temperature is that it assumes the two objects are in perfect thermal contact and there is no loss or gain of heat to the surrounding environment. In real-world scenarios, there may be external factors that can affect the final temperature, such as insulation or airflow.

5. Can the "trick" for finding final temperature be used in complex scientific experiments?

Yes, the "trick" for finding final temperature can be applied to complex scientific experiments as long as the principles of thermal equilibrium are followed. In more complex experiments, it may be necessary to consider additional factors such as phase changes or chemical reactions that can affect the final temperature. However, the same fundamental principles still apply.

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