This is a true statement right?

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SUMMARY

The discussion centers on the mathematical functions f(x) = x³ - 6x + c₂ and y = 5 - 3x, specifically their tangency at the point where x = 1. The user confirms that at x = 1, f(1) equals y(1), leading to the equation 13 - 6 + c₂ = 2, which allows for the determination of c₂. The reasoning presented is validated by other participants, affirming that the functions are indeed equivalent at the specified point.

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Saladsamurai
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If f(x)=x^3-6x+c_2 and I know that y=5-3x is tangent at the point where x=1,
then I can say that at x=1 f(x)=x^3-6x+c_2|_{x=1}=5-3x.
Right? and then I can solve for c_2

I am getting the correct answer to my text problem, but I want to be sure that it is because my reasoning is correct.

Casey
 
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I presume that by "f(x)=x^3-6x+c_2|_{x=1}", you mean f(1).
Your reasoning is correct but I would write f(1)= 13- 6(1)+ c2= 5- 3(1).
 
HallsofIvy said:
I presume that by "f(x)=x^3-6x+c_2|_{x=1}", you mean f(1).
Your reasoning is correct but I would write f(1)= 13- 6(1)+ c2= 5- 3(1).
I guess that is a shorter hand way of writing it. But I guess I wanted to be sure that it was indeed f(x)=y at x=1. That the function and the equation were equivalent.

Thanks,
Casey
 

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