This is the algorithm of Quicksort

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SUMMARY

The discussion focuses on the Quicksort algorithm, detailing its implementation and the significance of the swap operation within the algorithm. The provided pseudocode outlines the Quicksort and Partition functions, emphasizing the need for the swap operation after partitioning. The cost analysis reveals that when the pivot index $q$ is $p+1$, the cost of Partition is $O(n)$, leading to recursive calls that affect the overall time complexity. The worst-case cost is expressed as $T(n)=\max_{0 \leq q \leq n-1} (T(q)+T(n-q-1))+\Theta(n)$, highlighting the algorithm's performance in unfavorable scenarios.

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evinda
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Hi! (Nerd)

This is the algorithm of [m] Quicksort [/m], according to my notes:

Code:
Quicksort(A,p,r)
   if (p>=r) return;
   q=Partition(A,p,r);
   swap(A[q],A[r]);
   Quicksort(A,p,q-1);
   Quicksort(A,q+1,r)

Code:
Partition(A,p,r)
  x=A[r];
  i=p-1;
  for (j=p; j<r; j++){
       if (A[j]<=x){
          i=i+1;
          swap(A[i],A[j]);
       }
  }
  swap(A[i+1],A[r]);
  return i+1;

Why is this command: [m] swap(A[q],A[r]); [/m] needed at the algorithm of [m]Quicksort[/m]?
Don't we swap these values in [m] Partition [/m] ? (Thinking)
 
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Also, which is the cost when $q=p+1$ and which when $q=\lfloor \frac{p+r}{2} \rfloor$ ?

When $q=p+1$, we will have the cost of [m]Partition[/m] that is $O(n)$ and we will have to call the functions [m]Quicksort(A,p,p)[/m] and [m]Quicksort(A,p+,r)[/m], right? How can we find then the cost? (Thinking)Could you also explain me why this: $T(n)=\max_{0 \leq q \leq n-1} (T(q)+T(n-q-1))+\Theta(n)$ is the cost of the worst case? (Worried)
 
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