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## Homework Statement

Need to find the derivative:

y=logx/2-logx=logx*(2-log(x))^-1

## The Attempt at a Solution

The derivative of log(x) is 1/xln(10) and the derivative of (2-log(x))^-1 is -(2-log(x))^-2*1/xln(10)?

This ended as

1/xln(10)(2-logx) - logx/xln(10)(2-log(x))^2

2-log(x)-log(x)/xln(10)(2-log(x))^2

Though the answer is 2/xln(10)(2-log(x))^2... so what am I doing wrong?