(a) Find the x- and y-coordinates of the relative maximum points of f in terms of b. (b) Find the x- and y-coordinates of the relative minimum points of f in terms of b. (c) Show that for all values of b > 0, the relative maximum and minimum points lie on a function of the form y = -ax3 by finding the value of a. (a) f(x)=x3-3bx f'(x)=3x2-3b=0 x2=b x=+/-sqrt(b) when x=-sqrt(b), f(x) = y = -b3/2 - 3b(-b1/2) (x,y) = ( -sqrt(b) , 2b3/2) f has a maximum (b) when x=sqrt(b), f(x) = y = b3/2 - 3b(b1/2) (x,y)=(sqrt(b),-2b3/2) f has a minimum (c) I'm not sure. Can someone help me with (c)? Ok, i attempted each part. Did i do anything wrong?