This problem is driving me crazy

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SUMMARY

The problem involves calculating the force exerted by a car on a truck, where the car has a mass of 1000 kg and the truck has a mass of 2000 kg. The car pushes against the ground with a force of 4500 Newtons. Using Newton's third law, the force of the car on the truck is equal to the force exerted by the car, which is 4500 Newtons. The discussion emphasizes the importance of understanding action/reaction pairs and suggests that friction can be ignored in this scenario.

PREREQUISITES
  • Understanding of Newton's laws of motion, particularly Newton's third law
  • Basic knowledge of force calculations using F = m x a
  • Familiarity with free body diagrams for visualizing forces
  • Concept of friction and its coefficient in physics
NEXT STEPS
  • Study Newton's laws of motion in detail, focusing on action and reaction forces
  • Learn how to construct and analyze free body diagrams
  • Research the concept of friction and its coefficients in various scenarios
  • Explore practical applications of force calculations in real-world physics problems
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This problem is driving me crazy!

Homework Statement




What is the magnitude of the force of the car on the truck, when the mass of the car is 1000 kg, when the mass of the truck is 2000 kg, when the driver steps on the accelerator, the wheels of the car push against the ground with a force of 4500 Newtons. What is the magnitude of the force of the car on the truck? The car is pushing the truck, just to clarify, not the other way around.

The car is pushing the truck, there's no rope or chain or anything involved. It seems like there's some sort of information missing in this problem.

Homework Equations



F = m x a

Force / Normal force = coefficient of friction

The Attempt at a Solution



I started off by assuming you could find the force by multplying the mass times the acceleration, because of the fact that the problem gives you so little information, but that's incorrect. (1000 x 9.807)

I do know that all the forces given are in the y-direction, and there's no way to change that to x without finding the acceleration or the coeffecient of friction. I'm not quite sure if you can use the Newtons as the force to find a coefficient of friction, in which case I got 4500/9800, which is equal to .46 for the frictional coefficient, but I'm not sure if that's right or not.

Someone please help!
 
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Have you considered using Newton's 3rd law for this problem? That is, try drawing a free body diagram, list all of the action/reaction pairs, and try to figure out what happens physically before you try applying mathematics.

Also, I think you must be a little confused if you are using gravity as an acceleration because the car and truck will not be accelerating through the ground. In fact, Newton's third law would show that the weight of the cars on the Earth is the same as the Earth's push on the cars.

*P.S. I think you are able to ignore friction in this case.
 

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