Three conductors, how is the middle one affected

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SUMMARY

The discussion centers on the interaction between three parallel conductors carrying equal currents in the same direction. The middle conductor experiences a net force due to the magnetic fields generated by the outer conductors. Using the formula F = k * I(1) * I(2) * l / a, it is established that the attraction from the right conductor is greater than that from the left, resulting in the middle conductor moving to the right. The right-hand rule confirms this directional movement, leading to the conclusion that the middle conductor will indeed move to the right.

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Homework Statement


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We have three equally long conductors with equali distance between each. I have simply drawn it badly. The difference is their currents, they all go in the same direction. How is the middle one effected?

- It goes to the right
- It goes to the left
- It goes up from screen
- It goes down the screen
- Nothing happens

Homework Equations


B = k * (I/a) and F = I L B

The Attempt at a Solution


From the above equations we get the formula F = k * I(1) * I(2) * l (length) split by a (distance between two conductors).

What this means is that the force that the conductor with a current of 3A exerts on the middle one is the same as the middle conductor exerts on 3A. Through the use of the right hand rule (http://figures.boundless.com/14036/full/figure-23-04-01a.jpe) we'd see that the middle conductor and the conductor to the right are attracted and the left conductor and the middle conductor are also attracted.

Now, since the attraction to the right is double the size, that will surely overcome the one on the left and therefore the answer is "it goes to the right".

Am I missing something here?
 
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Looks good.
Conductors don't end somewhere, that would violate charge conservation (for continuous currents), but that is not relevant for the problem here.
 

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