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Three conductors, how is the middle one affected

  1. Dec 16, 2014 #1
    1. The problem statement, all variables and given/known data
    YkgYU1I.png We have three equally long conductors with equali distance between each. I have simply drawn it badly. The difference is their currents, they all go in the same direction. How is the middle one effected?

    - It goes to the right
    - It goes to the left
    - It goes up from screen
    - It goes down the screen
    - Nothing happens

    2. Relevant equations
    B = k * (I/a) and F = I L B

    3. The attempt at a solution
    From the above equations we get the formula F = k * I(1) * I(2) * l (length) split by a (distance between two conductors).

    What this means is that the force that the conductor with a current of 3A exerts on the middle one is the same as the middle conductor exerts on 3A. Through the use of the right hand rule (http://figures.boundless.com/14036/full/figure-23-04-01a.jpe) we'd see that the middle conductor and the conductor to the right are attracted and the left conductor and the middle conductor are also attracted.

    Now, since the attraction to the right is double the size, that will surely overcome the one on the left and therefore the answer is "it goes to the right".

    Am I missing something here?
     
  2. jcsd
  3. Dec 16, 2014 #2

    mfb

    User Avatar
    2016 Award

    Staff: Mentor

    Looks good.
    Conductors don't end somewhere, that would violate charge conservation (for continuous currents), but that is not relevant for the problem here.
     
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