(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Three polarizers are arranged as shown in the figure. If the incident beam of light is unpolarized, and has an intensity of 1.60 W/m2, find the transmitted intensity for each of the following cases.

(a) θ2 = 29.6° and θ3 = 44.0°

(b) θ2 = 44.0° and θ3 = 29.6°

2. Relevant equations

I= 1/2I_{0}

I= I_{0}cos^{2}θ

3. The attempt at a solution

So what I did what for the first area i used

I= 1/2I_{0}and I got .8

then I_{2}= .8cos^{2}(29.6)= .6048

then for I_{3}= .6048cos^{2}(44.0) =.2918

then i did the same for part b only switched the theta as needed.

Both of the answers are wrong. Ive been trying to think of why this could be wrong. I have tried many different ways, but this seems to be the one that makes most sense to me. If i could get any help that would be nice. Thanks in advance.

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

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# Three polarizers are arranged as shown in the figure

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