Throwing a rock - simple mechanics problem

  • Thread starter Thread starter Glyper
  • Start date Start date
  • Tags Tags
    Mechanics Rock
Click For Summary
SUMMARY

The discussion focuses on solving a mechanics problem involving projectile motion, specifically the trajectory of a rock thrown at a 30-degree angle with an initial velocity of 12 m/s. The maximum height (h) calculated using the formula h_{max}=\frac{v_0^2\cdot\sin^2\alpha}{2g} results in 2 meters. The range (Z) is determined using Z=\frac{v_0^2\cdot\sin 2\alpha}{g}, yielding a distance of 12 meters. The calculations are confirmed to be correct based on the provided equations.

PREREQUISITES
  • Understanding of projectile motion principles
  • Familiarity with trigonometric functions, specifically sine and cosine
  • Knowledge of gravitational acceleration (g = 9.81 m/s²)
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Study the derivation of projectile motion equations
  • Explore the effects of varying launch angles on projectile range
  • Learn about air resistance and its impact on projectile motion
  • Investigate real-world applications of projectile motion in sports and engineering
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in understanding the principles of projectile motion and its applications.

Glyper
Messages
27
Reaction score
0

Homework Statement



A rock was thrown at the angle of 30 degrees against the horizontal surface, being given a velocity V_0=12m/s. Find the largest height h and the Z - the range of the throw.

Homework Equations



h_{max}=\frac{v_0^2\cdot\sin^2\alpha}{2g}
Z=\frac{v_0^2\cdot\sin 2\alpha}{g}

The Attempt at a Solution



h_{max}=\frac{v_0^2\cdot\sin^2\alpha}{2g}=\frac{144*0,25}{2g}=2m
Z=\frac{v_0^2\cdot\sin 2\alpha}{g}=\frac{144\sqrt{3}/2}{9,81}=12m

Is that OK?
 
Physics news on Phys.org
Looks fine to me, if you can use those equations directly.
 
I suppose I will be allowed to :) Thank you.
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
1K
Replies
4
Views
3K
  • · Replies 21 ·
Replies
21
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
11
Views
3K
Replies
8
Views
4K
Replies
4
Views
2K
  • · Replies 8 ·
Replies
8
Views
6K