Ti-89 Limit of Integral undefined BUT it is 4 both by hand and Mathematica

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SUMMARY

The TI-89 Titanium calculator returns an undefined result for the limit of the integral inputted as limit(S((2 x cos(100 x Pi x t)+2 x sin(10 x Pi x t))^2 ,t,-t1,t1)/(2 x t1),t1,inf). In contrast, both manual calculations and Wolfram Mathematica confirm that the limit is 4. The discrepancy arises from the TI-89's handling of the integral, which yields a different expression than Mathematica's, leading to confusion regarding the correct limit evaluation.

PREREQUISITES
  • Understanding of limits in calculus
  • Familiarity with integral calculus
  • Experience using the TI-89 Titanium calculator
  • Knowledge of Wolfram Mathematica syntax and functions
NEXT STEPS
  • Review the TI-89 Titanium manual for proper syntax in limit and integral calculations
  • Explore advanced features of Wolfram Mathematica for integral evaluation
  • Study the properties of Fourier series and their applications in limits
  • Investigate common pitfalls in using graphing calculators for complex calculus problems
USEFUL FOR

Students and educators in mathematics, particularly those focusing on calculus, as well as users of the TI-89 Titanium and Wolfram Mathematica seeking to resolve discrepancies in computational results.

Tspyros
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I am giving the following input to Ti-89 Titanium:

limit(S((2 x cos(100 x Pi x t)+2 x sin(10 x Pi x t))2 ,t,-t1,t1)/(2 x t1),t1,inf)

where S is the integral symbol, Pi is π = 3.14, x is the multiplication symbol and inf is the infinity symbol

The TI-89 answer is undef

If I do it by hand it is 4 and Wolfram Mathematica with the following input agrees:

Limit[Integrate[(2Sin[10Pit] + 2Cos[100Pit])2, t, -T, T}]/(2*T), T -> Infinity]

Do you see any errors in my TI89 input?

(I have made the same question in the Ti89 subreddit but it doesn't seem to be used by more than 5 people.)

Thank you!

Some more info:

For the integral alone the Ti89 gives:

-20 π T-10 sin(10 π T) cos(10 π T)+sin(100 π T) cos(100 π T))/((25 π)

whereas mathematica gives:

(400 π T - 10 Sin[20 π T] + Sin[200 π T])/(50 π) with the limit again 4 in Mathematica

If I limit the Ti-89 result with mathematica, it returns -2/5
 
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Thanks for the post! Sorry you aren't generating responses at the moment. Do you have any further information, come to any new conclusions or is it possible to reword the post?
 
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