# Homework Help: Time dependent position given position dependent force

1. Sep 1, 2015

### scoopaloop

1. The problem statement, all variables and given/known data
A particle of mass m is subject to a force F(x) = −kx^−2 (1) that attracts it toward the origin. (a) Determine the potential energy function U(x), defined by F(x) = − d U(x)/dx. (b) Assuming that the particle is released from rest at a position x0, show that the time t required for the particle to reach the origin is t = π sqrt(m/8k)(x_0)^(3/2)

2. Relevant equations
dt=dx/sqrt(2(E-U)/m)

3. The attempt at a solution
So, I found The potential energy to be k/x using that and the fact that at v=0 at x_0, I get dt=dx/sqrt(2((k/x_0)-k/x)/m). My only problem is integrating this I get a long nasty function that I feel I can't get x isolated. Maybe, I'm being lazy and need to gut through it, but is there an easier way to approach this?

2. Sep 1, 2015

### Orodruin

Staff Emeritus
If we are to have any chance of helping you, you need to actually show us what you did.

3. Sep 1, 2015

### scoopaloop

I just want to know if this is the correct approach or if there is another way. I'm not asking you to do it for me. I'd imagine you either know how to do this problem or you don't, I don't see how writing some long pain in the butt equation will help you know how to do the problem.

Last edited: Sep 1, 2015
4. Sep 1, 2015

### Orodruin

Staff Emeritus
The approach is fine, but you seem to be doing it wrong. You can easily factor out the dependence on $x_0$ by a change of variables and obtain a dimensionless integral.

You can also argue for the correct dependence of the time on $x_0$, $k$, and $m$ purely on dimensional grounds. There is only one combination of these parameters which results in a time. Of course, you still need to perform the integral to get the correct prefactor.

Share this great discussion with others via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted