I Time derivative of the angular momentum as a cross product

Click For Summary
The discussion focuses on deriving the equations of motion for angular momentum in a system with a particle and a magnetic moment in a magnetic field. The Hamiltonian is defined, leading to the time evolution equation for angular momentum as a cross product involving the magnetic field. The identification of the term related to angular velocity with the expression for angular momentum evolution raises questions about its justification. The user seeks clarification on the significance of this identification and its relation to known concepts like Larmor precession. Understanding this relationship is crucial for grasping the dynamics of the system.
AndersF
Messages
27
Reaction score
4
I am trying to find the equations of motion of the angular momentum ##\boldsymbol L## for a system consisting of a particle of mass ##m## and magnetic moment ##\boldsymbol{\mu} \equiv \gamma \boldsymbol{L}## in a magnetic field ##\boldsymbol B##. The Hamiltonian of the system is therefore

##H=\frac{p^{2}}{2 m}-\gamma \boldsymbol{L} \cdot \boldsymbol{B}##

I have found that the time evolution equation for the angular momentum is

##\frac{d \boldsymbol{L}}{d t}=-\gamma \boldsymbol{B} \times \boldsymbol{L}##

However, the solution identifies the term ##-\gamma \boldsymbol{B}## with the angular velocity ##\boldsymbol{\Omega}##:

##\frac{d \boldsymbol{L}}{d t}=\boldsymbol{\Omega} \times \boldsymbol{L}##

I do not understand what the justification is for making this identification. This last equation looks familiar to me, but I'm not sure where I've seen it... Could someone give me some guidance on this?
 
Physics news on Phys.org
I think he introduced a new parameter defined as
\Omega:=-\gamma B.
 
Okay, but does the formula ##\frac{d \boldsymbol{L}}{d t}=\boldsymbol{\Omega} \times \boldsymbol{L}## have any special meaning, being ##\boldsymbol{\Omega}## the angular velocity?
 
For fun I was trying to use energy considerations to determine the depth to which a solid object will sink in a fluid to reach equilibrium. The first approach that I tried was just to consider the change in potential energy of the block and the fluid as the block is lowered some unknown distance d into the fluid similar to what is shown in the answer to this post. Upon taking the limit as the vessel's cross sectional area approaches infinity I have an extra factor of 2 in the equilibrium...

Similar threads

Replies
1
Views
2K
Replies
4
Views
2K
Replies
7
Views
2K
Replies
4
Views
2K