Time dilation - Lorentz transformation using light clock

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SUMMARY

The discussion focuses on deriving the time dilation formula using the Lorentz transformation and the Pythagorean theorem. The user initially misapplies the relationship between the distances and times in different frames, specifically confusing the terms D and L. The correct formula for time dilation is established as t' = t / √(1 - v²/c²), where t is the proper time and v is the relative velocity. The clarification emphasizes the importance of correctly identifying the reference frames in the context of special relativity.

PREREQUISITES
  • Understanding of Lorentz transformation in special relativity
  • Familiarity with the concept of time dilation
  • Knowledge of the Pythagorean theorem
  • Basic principles of reference frames in physics
NEXT STEPS
  • Study the derivation of the Lorentz transformation equations
  • Learn about the implications of time dilation in high-velocity scenarios
  • Explore examples of time dilation in GPS satellite technology
  • Investigate the relationship between simultaneity and reference frames in special relativity
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Students of physics, educators teaching special relativity, and anyone interested in understanding the mathematical foundations of time dilation and Lorentz transformations.

kapitan90
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Homework Statement


I am trying to derive the time dilation formula using Pythagorean theorem:
L = ct (in clocks rest frame)
D = ct'(in observer's frame, the clock moving with velocity u)

The Attempt at a Solution



So D^2 = L^2 +v^2t^2
c^2{t'}^2=c^2t^2+u^2t^2
Sot'=t*\sqrt{1+v^2/c^2}
but it should be
t'=t/\sqrt{1-v^2/c^2}

Homework Equations


This would work if D=ct, not ct' and L=ct', but I guess it isn't right with my choice of frames of reference?

Sources: http://www.drphysics.com/syllabus/time/time.html
 

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kapitan90 said:
This would work if D=ct, not ct' and L=ct', but I guess it isn't right with my choice of frames of reference?
You're mixing up your frames a bit. The clock moves a distance vt' (not vt) in the observer's frame. (The observer uses his own time measurements, of course.)
 
Ok, now it works, thanks for your reply!
 

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