Time for light to reach earth homework

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Homework Help Overview

The discussion revolves around calculating the time it takes for light to travel from the Sun to Earth, the time for signals from Saturn to reach Earth, and determining the temperature of a light bulb filament based on its wavelength. Additionally, participants are tasked with calculating the mass of Jupiter using the orbit of Ganymede.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between distance, speed, and time for light travel, with some expressing uncertainty about specific calculations. There are attempts to apply relevant equations for temperature based on wavelength, and questions arise regarding the mass calculation of Jupiter, with some participants questioning the validity of the results presented.

Discussion Status

Some participants have provided partial calculations and expressed confusion over certain aspects of the problems. There is a mix of attempts to clarify concepts and calculations, with no clear consensus on the correctness of the methods used or the results obtained.

Contextual Notes

Participants are encouraged to list relevant equations and show their work, indicating a focus on understanding the problem-solving process rather than just obtaining answers. There is mention of formatting issues that may have affected the clarity of the original posts.

phys1120
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QUESTION 1 (3 points):
a) Given that the Sun is 150,000,000 km from Earth, how long does it take
light to travel from the Earth to the Sun. Give your answer in minutes (min)

b) The Cassini spacecraft , currently in orbit about Saturn, sends its data to
Earth using radio waves. Assume that Saturn is at its closest approach to
Earth. How long does it take the signals to reach Earth from Saturn? Give
your answer it minutes (min).

QUESTION 2 (3 points):
A regular incandescent light bulb radiates most strongly at a wavelength of
3000 nm.
a) How hot is the filament? Give your answer in Kelvins (K)

b) In which part of the spectrum does it emit the most radiation: visible, or
infrared (heat)?

QUESTION 3 (6 points):
Use the orbit of Ganymede to calculate the mass of Jupiter in kilograms. You
will need to use the size of the orbit and orbital period, which can be found in
Table 8.1 on page 216 of the 6th edition of the text. (Any other text boox will
have a table of appendix with this information. Remember that the units to
calculate the mass have to be in metres, and seconds if you want to get the
mass in kilograms.
 
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Generally, we expect people who want help with homework to list all relevant equations and show their attempt at all questions. Please do this and we'll help you.

BTW, this should really go in the "Homework and Coursework" section.
 
#1a) time = distance
speed
time = 150,000,000
299,792.458m/s
time = 150,000,000
482,469,193.528km/s
time = 0.3109km/s
time = 18.654km/m
b) NO IDEA!

#2a) wavelength = 1
temperature
3000nm = 2.9 x10^6
temperature
3000nm = 2,900,000
temperature
temperature = 966.667
b)infrared

#3) M = 4pie^2a^3
GP^2
M = 39.478 x 1634.206m^3
6.7 7.15^2
M = 5.892 x 2,417,217.876
51.123
M = 5.892 x 47,285.17
M = 278,604.222
 
I think there was a problem that messed up your formatting and deleted some of your text, but I'll help the best I can.

phys1120 said:
#1a) time = distance
speed
time = 150,000,000
299,792.458m/s
time = 150,000,000
482,469,193.528km/s
time = 0.3109km/s
time = 18.654km/m
b) NO IDEA!

For 1a), all you need to know is that time equals distance divided by speed. This should be obvious; if you're driving at 40 km/h, you'd take one hour to cover 40 km, 2 hours to cover 80 km, and so on. The speed of light is 299 792.458 km/s (not m/s) and the distance from the Sun to the Earth is 150 000 000 km. So how many seconds does it take sunlight to reach earth?

For 1b), try looking at the back of your textbook for the orbital parameters of Saturn and Earth. How far is Saturn from Earth at closest approach?

#2a) wavelength = 1
temperature
3000nm = 2.9 x10^6
temperature
3000nm = 2,900,000
temperature
temperature = 966.667
b)infrared

All of this is correct.
#3) M = 4pie^2a^3
GP^2
M = 39.478 x 1634.206m^3
6.7 7.15^2
M = 5.892 x 2,417,217.876
51.123
M = 5.892 x 47,285.17
M = 278,604.222

I can't follow this, but 278 604 kg can't possibly be right. That's 278 tons, about the weight of a Boeing 747, but Jupiter is a planet much more massive (by far) than the Earth.
 

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