Time given angular velocity/displacement

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A gymnast's tumbling run involves increasing her angular velocity from 2.90 to 5.40 revolutions per second while completing a half-revolution. The initial angular velocity is converted to radians per second, resulting in 18.22 rad/s and 33.92 rad/s for the final velocity. The equation θ = 1/2 (w0 + w) t is used to find the time, but the initial calculation was incorrect due to mixing radians and degrees. After correcting the angle to radians, the time taken for the maneuver is calculated as approximately 0.12044 seconds. Accurate unit conversion is crucial in solving angular motion problems.
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A gymnast is performing a floor routine. In a tumbling run she spins through the air, increasing her angular velocity from 2.90 to 5.40 rev/s while rotating through one half of a revolution. How much time does this maneuver take?

Knowns:
w0 = 2.9 rev/sec * 2pi rad = 18.22 rad/sec
w = 5.4 rev/sec * 2pi rad = 33.92 rad/sec
θ = 180?

θ = 1/2 (w0 + w) t
180 = 1/2 (18.22 + 33.92) t
180 = 1/2 (52.14) t
(/180) 180 t = 26.07 (/180)
t = .1448

I know this is incorrect, and would appreciate help in the right direction.
 
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Don't mix radians and degrees!
 
Got it! :D

θ = 180 deg *(pi/180) = 3.14 rad

ω = 26.07

θ = ωt

which turns into

t = θ/ω

t = .12044
 
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