Time independent wave function (prove theorem)

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The discussion centers on proving that the time-independent wave function, denoted as ψ(x), can always be expressed as a real function, even if the original function is complex. It emphasizes that any complex solution can be represented as a linear combination of real solutions with the same energy. The hint provided suggests using the complex conjugate of ψ(x) to derive real linear combinations. Participants express confusion about how to apply this concept and incorporate the hint into their understanding. The overall goal is to demonstrate that real-valued wave functions can adequately represent the solutions to the time-independent Schrödinger equation.
Cogswell
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Homework Statement


Prove the following theorum:
The time-independent wave function ## \psi (x) ## can always be taken to be real (unlike ##\Psi (x,t) ##, which is necessarily complex). This doesn't mean that every solution to the time independent Schrodinger equation is real; what it says is that if you've got one that is not, it can always be expressed as a linear combination of solutions (with the same energy) that are. So you might as well stick to ## \psi## 's that are real.
Hint: If ## \psi(x)## satisfies equation [1.0], for a give E, so too does its complex conjugate, and hence also the real linear combinations ##( \psi + \psi ^*)## and ##i( \psi - \psi ^*)##


Homework Equations


Equation [1.0]:

E \psi = -\dfrac{\hbar ^2}{2m} \dfrac{d^2 \psi}{dx^2} + V \psi


The Attempt at a Solution



I don't fully get what it. So it's saying that if I have a ## \psi (x) ## that is a complex function of x, then that can somehow be expressed in the form:

## \psi_{complex} (x) = \psi_1 (x) + \psi_2 (x) + \psi_3 (x) ...##

How does that work? I also don't know how to incorporate the hint into it.

(Sorry quantum mechanics isn't my strong point so it would help if you explained it to me in simple terms)
 
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Cogswell said:

Homework Statement


Prove the following theorum:
The time-independent wave function ## \psi (x) ## can always be taken to be real (unlike ##\Psi (x,t) ##, which is necessarily complex). This doesn't mean that every solution to the time independent Schrodinger equation is real; what it says is that if you've got one that is not, it can always be expressed as a linear combination of solutions (with the same energy) that are. So you might as well stick to ## \psi## 's that are real.
Hint: If ## \psi(x)## satisfies equation [1.0], for a give E, so too does its complex conjugate, and hence also the real linear combinations ##( \psi + \psi ^*)## and ##i( \psi - \psi ^*)##

Homework Equations


Equation [1.0]:

E \psi = -\dfrac{\hbar ^2}{2m} \dfrac{d^2 \psi}{dx^2} + V \psi

The Attempt at a Solution



I don't fully get what it. So it's saying that if I have a ## \psi (x) ## that is a complex function of x, then that can somehow be expressed in the form:

## \psi_{complex} (x) = \psi_1 (x) + \psi_2 (x) + \psi_3 (x) ...##

How does that work? I also don't know how to incorporate the hint into it.

(Sorry quantum mechanics isn't my strong point so it would help if you explained it to me in simple terms)
Do you know how to express the real and imaginary parts of a complex number z in terms of z and z*? (If not, write down the definition of z* and figure it out).

Note that the eigenfunctions of H are supposed to span the entire space of functions that we're dealing with. If ##f_1,f_2,\dots## are eigenfunctions of H with eigenvalues ##E_1,E_2,\dots##, then the set ##\{f_n\}_{n=1}^\infty## is a basis for that space. Your job is to take an arbitrary basis like that and find a way to replace it with one that consists only of real-valued functions.
 
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