Time it takes a 3-body gravitational system to complete one orbit?

In summary, there is no general analytical solution for the motion of a three-body gravitational system, but there are analytical solutions for special initial conditions. The system in question involves three stars of equal mass moving in a two-dimensional plane along a circle of radius r. The task is to calculate the time it takes for the system to make one complete revolution. This can be done by using the Momentum Principle and finding the net gravitational force on any given star due to the other two. The three stars form an equilateral triangle, and each lies on a point of the circle's radius.
  • #1
UTlonghorn
2
0

Homework Statement



There is no general analytical solution for the motion of a three-body gravitational system. However, there do exist analytical solutions for very special initial conditions. The figure below (see attachment) shows three stars, each of mass m, which move in a two-dimensional plane along a circle of radius r. Calculate how long this system takes to make one complete revolution. (In many cases, three-body orbits are not stable: any slight perturbation leads to a breakup of the orbit.)

Homework Equations



This course focuses heavily on the Momentum Principle.

mv2/R=GMm/R2

v=(GM/R)1/2

v=(2(pi)R)/T

(2(pi)R)/T=(GM/R)1/2 where T is the time it takes to complete one complete revolution.

The Attempt at a Solution



I thought you could just replace Mm with m3 since the stars all have equal mass and then solve for T, but it's not in the answer choices. The answer is one of the choices in the attachment.
 

Attachments

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  • #2
You'll need to work out the net gravitational force that anyone of the stars feels from the other two. By symmetry this should be directed towards the center of the circle.

What sort of triangle do the stars form, if the stars are at the vertexes?
 
  • #3
I have this same problem too. The three bodies are arranged in an equilateral triangle, and each of them lay on a point of the radius of the circle.

Update: My bad, I thought you could not see the attached pictures.
 
Last edited:
  • #4
The same advice as before applies. Find an expression for the net gravitational force on any given body due to the other two. That net force provides the centripetal force required to move the body in circular motion...
 
  • #5


I would like to point out that the provided equations and attempt at a solution are incorrect. The equations provided are for a two-body system, not a three-body system. Additionally, the given initial conditions of a circular orbit are not consistent with the general motion of a three-body system.

In order to accurately determine the time it takes for a three-body gravitational system to complete one orbit, more information is needed. This includes the masses of each body, their initial positions and velocities, and the shape of their initial orbits. Without this information, it is not possible to accurately calculate the time it takes for the system to complete one orbit.

Furthermore, as stated in the problem, three-body orbits are often unstable and can easily be disrupted by even small perturbations. This means that the time it takes for the system to complete one orbit may vary greatly depending on the initial conditions and any external influences.

In summary, the time it takes for a three-body gravitational system to complete one orbit cannot be accurately calculated without more information and considering the potential instability of the system.
 

1. How is the time for a 3-body gravitational system to complete one orbit calculated?

The time for a 3-body gravitational system to complete one orbit can be calculated using Kepler's Third Law, which states that the square of a planet's orbital period is proportional to the cube of the semi-major axis of its orbit. This law can be applied to a 3-body system by considering the combined mass of all three bodies and the distance between their center of masses.

2. Does the time for a 3-body gravitational system to complete one orbit depend on the masses of the bodies involved?

Yes, the time for a 3-body gravitational system to complete one orbit is directly proportional to the masses of the bodies involved. This means that the more massive the bodies are, the longer it will take for them to complete one orbit.

3. Can the time for a 3-body gravitational system to complete one orbit be affected by external forces?

Yes, external forces such as the gravitational pull of other objects or the effects of relativity can affect the time for a 3-body gravitational system to complete one orbit. These forces can cause slight variations in the orbital period of the bodies.

4. Is the time for a 3-body gravitational system to complete one orbit constant?

No, the time for a 3-body gravitational system to complete one orbit is not constant. As the bodies move around each other, their positions and velocities change, causing slight variations in the time it takes for them to complete one orbit. However, these variations are usually very small and can be calculated using advanced mathematical models.

5. Can the time for a 3-body gravitational system to complete one orbit be used to determine the masses of the bodies?

Yes, the time for a 3-body gravitational system to complete one orbit can be used, along with other observational data, to determine the masses of the bodies involved. This is known as the "mass-inclination" method and is commonly used in astronomy to study multiple body systems.

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