# Time of satellite orbit around moon?

## Homework Statement

What is the time of an orbit of a satellite around the moon close to the moon's surface? What quantities do you have to look up to be able to answer this question?

Radius of moon is 1736482 meters

F = Gm1m2/r^2
and maybe
F=mv^2/r

2pir

## The Attempt at a Solution

1. 2 pi (1736482 meters) = 10910638.19 m = distance around moon
.....and thats all I have. I don't know how to achieve time just given a radius. I do know that centripetal force has to come into play somewhere.

I'm so lost!

Bandersnatch
Hi Dillion.

Let's take it step by step.

For an object to move in circles (e.g. an orbit), what magnitude must the net force acting on it be?

PeroK
Homework Helper
Gold Member
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You have the two key equations. Do you understand them? What does ##F=mv^2/r## mean?

Hi Dillion.

Let's take it step by step.

For an object to move in circles (e.g. an orbit), what magnitude must the net force acting on it be?

I hate to say this but I don't even know what you're asking.....

You have the two key equations. Do you understand them? What does ##F=mv^2/r## mean?

Is it the force something creates while going around in a circle? When I see this equation I think about tension force and a ball on a string being swung around.

F = Gm1m2/r^2 is the gravitational force of an object a certain distance away from the moon.

I think a light bulb just clicked...

G = 6.67 x 10 ^-11
M1 = I will make it up to be a mass of an object lets say 1 kg
M2 = mass of moon which is 7.35 × 10^22 kg
r = 1736482 meters

When I plug those value into F = Gm1m2/r^2, I get F = 2823208.072. I can set this as the F in F = mv^2/r.

2823208.072 = (1kg) (v^2) / 1736482

solving for v^2, v = 2214147.7 m/s

Velocity = distance / time..... so 2214147.7 = 10910638.19 / time.

time = 4.9 seconds.

is this right?

Bandersnatch
You've got the procedure figured out right, but:
F = Gm1m2/r^2, I get F = 2823208.072.
You've made a mistake in calculations here. Try again, and make sure you plug in everything into the equation. See what result you get then.

Once you've got that done, we can talk about what the equation means, and why it was even a good idea to use it here.

• PeroK
You've got the procedure figured out right, but:

You've made a mistake in calculations here. Try again, and make sure you plug in everything into the equation. See what result you get then.

Once you've got that done, we can talk about what the equation means, and why it was even a good idea to use it here.

Okay I forgot the square the radius :(

but after I redid my calculations I got 1.63 for F

1.63 = (1kg) (v^2) / 1736482

solving for v^2, v = 1682.4 m/s

Velocity = distance / time..... so 1682.4 = 10910638.19 / time.

time = 6485.16 seconds.

second time the charm?

Bandersnatch