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Time on watch dependent on air temperature?

  • Thread starter kriegera
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  • #1
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Homework Statement


Can anyone give me a hand on how to start this? I would attempt a solution but I've tried over and over and can't seem to get anywhere.

A man sets his watch at noon by the sound of a factory whistle 3 miles away. If the temperature of the air is 20-degrees C, how many seconds slow will his watch be by the time at the factory?


Homework Equations





The Attempt at a Solution

 

Answers and Replies

  • #2
DaveC426913
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How fast does sound travel through air at 20C?
 
  • #3
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How fast does sound travel through air at 20C?

Still a little lost here:

In general, at 68 F (20 C) sound travels at 1130 ft/sec (344.4 m/sec.)
3 miles = 15 840 feet
3 miles = 4 828.032 meters

but not sure how to put it together in equation format?
 
  • #4
DaveC426913
Gold Member
18,708
2,195
Still a little lost here:

In general, at 68 F (20 C) sound travels at 1130 ft/sec (344.4 m/sec.)
3 miles = 15 840 feet
3 miles = 4 828.032 meters

but not sure how to put it together in equation format?
Really?

You've got a velocity and a distance; you're being asked to solve for time.

You say you're tried over and over. Show your attempts.
 
  • #5
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Really?

You've got a velocity and a distance; you're being asked to solve for time.

You say you're tried over and over. Show your attempts.
T=V/D =
T=15840 ft/ 1130ft/s = 14.018 seconds.
 
  • #6
DaveC426913
Gold Member
18,708
2,195
T=V/D =
T=15840 ft/ 1130ft/s = 14.018 seconds.
Does that sound about right? What does your intuition tell you? Think of thunder & lightning.
 
  • #7
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Does that sound about right? What does your intuition tell you? Think of thunder & lightning.
I did find something that used c = d / Δ t - where c was speed of sound so
Δ t = d / c = 15,840/344.4 = 46 seconds but that seems too long a delay for three miles no?

As far as thunder and lightning, lightning strikes first b/c it travels faster in air than sound. The speed of a sound wave in air depends upon the properties of the air, namely the temperature and the pressure so it makes sense for
Time=distance/speed =
Time=15,840 ft/1130 ft/sec.
14.018 sec

but i'm still second-guessing it.
 

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