Time period of Beat (acoustics)

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SUMMARY

The discussion centers on the mathematical representation of beats in acoustics, specifically the equation $$y=2 A \cos 2 \pi\left(\frac{\nu_{1}-\nu_{2}}{2}\right) t \sin 2 \pi\left(\frac{\nu_{1}+\nu_{2}}{2}\right) t$$. This equation is derived from the superposition of two sinusoidal waves with different frequencies, represented as $$y_{1}=A \sin \omega_{1} t$$ and $$y_{2}=A \sin \omega_{2} t$$. The time period of the beats is determined by the difference in frequencies, expressed as $$T=\dfrac{1}{\nu_{1}+\nu_{2}}$$, while the beat frequency is given by $$n=\nu_{1} \sim \nu_{2}$$. The discussion also touches on the relationship between amplitude and the time period of beats.

PREREQUISITES
  • Understanding of wave mechanics and oscillations
  • Familiarity with trigonometric identities, particularly the sum of sine waves
  • Knowledge of frequency and amplitude in the context of sound waves
  • Basic grasp of acoustic phenomena, specifically beats
NEXT STEPS
  • Study the derivation of the beat frequency formula in acoustics
  • Learn about the effects of amplitude on sound wave interference
  • Explore the relationship between frequency and time period in wave mechanics
  • Investigate practical applications of beats in music and audio engineering
USEFUL FOR

Students of physics, audio engineers, and anyone interested in understanding the principles of sound wave interference and the phenomenon of beats.

Huzaifa
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$$y=2 A \cos 2 \pi\left(\frac{\nu_{1}-\nu_{2}}{2}\right) t \sin 2 \pi\left(\frac{\nu_{1}+\nu_{2}}{2}\right) t$$

Can you explain me the significance of the above equation in the context of waves and oscillations? It's something to do with 'beats,'.
 
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Where did you get it from? They probably derive it from the combination of the two sinusoids at different frequencies, no?
 
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https://en.wikipedia.org/wiki/Beat_(acoustics)

1641320559632.png
 
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berkeman said:
Where did you get it from? They probably derive it from the combination of the two sinusoids at different frequencies, no?
Yes sir, they derived it from $$y_{1}=A \sin \omega_{1} t ; y_{2}=A \sin \omega_{2} t$$
 
$$y=y_{1}+y_{2}=A\left[\sin \omega_{1} t+\sin \omega_{2} t\right]=A\left[2 \sin \left(\frac{\omega_{1}+\omega_{2}}{2}\right) t \cos \left(\frac{\omega_{1}-\omega_{2}}{2}\right) t\right]$$

How to proceed ahead from here?
 
Huzaifa said:
$$y=y_{1}+y_{2}=A\left[\sin \omega_{1} t+\sin \omega_{2} t\right]=A\left[2 \sin \left(\frac{\omega_{1}+\omega_{2}}{2}\right) t \cos \left(\frac{\omega_{1}-\omega_{2}}{2}\right) t\right]$$

How to proceed ahead from here?
Sorry, what do you mean? Are you familiar with common trig identities like the sum of two sine waves?

https://www.purplemath.com/modules/idents.htm

1641321981618.png
 
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Consider two two sinusoids at different frequencies $$y_{1}=A \sin \omega_{1} t ; y_{2}=A \sin \omega_{2} t$$
$$y=y_{1}+y_{2}=A\left[\sin \omega_{1} t+\sin \omega_{2} t\right]=A\left[2 \sin \left(\frac{\omega_{1}+\omega_{2}}{2}\right) t \cos \left(\frac{\omega_{1}-\omega_{2}}{2}\right) t\right]$$

For the formation of waxing, A is maximum, what will be the time period? And for the formation of wanning, A is minimum, what will be the time period?
unknown.png

This is from my class notes. Unfortunately, I missed my class and I am not able to understand now. So I have turned to Physics Forums for help.

Please explain me how the time period for the formation of beat T, $$T=\dfrac{1}{\nu_{1}+\nu_{2}}$$
and the beat frequency $$n=\nu_{1} \sim \nu_{2}$$
 
Huzaifa said:
How to solve for time period now?
Which time period? The sound you hear when listening to audio beats is the sum frequency, modulated at the difference frequency. So the period of the beats (the louder-softer characteristic) is at the difference frequency of the two sine waves.
 
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berkeman said:
Which time period? The sound you hear when listening to audio beats is the sum frequency, modulated at the difference frequency. So the period of the beats (the louder-softer characteristic) is at the difference frequency of the two sine waves.
Yes, I think the time period of the beats. Does the time period depend on A? When the A is maximum, $$t=\dfrac{n}{\nu_1-\nu_2}$$, When A is minimum $$t=\dfrac{2n+1}{2 \left( \nu_1-\nu_2 \right)}$$.
 

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