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neha1
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two trains 200 meters and 150 metrers are running on the parallel raila at this rate of 40km/hr and 45 km/hr.in how time will they cross each other if they are running in the same direction?
Hi neha1 and welcome to PF,neha1 said:two trains 200 meters and 150 metrers are running on the parallel raila at this rate of 40km/hr and 45 km/hr.in how time will they cross each other if they are running in the same direction?
The time it takes for a train to cross a distance can be calculated using the formula: time = distance / speed. In this case, the distance is given as 200m and 150m, and the speeds are 40km/hr and 45km/hr respectively. So, the time for the first train to cross 200m would be 200m / 40km/hr = 5 seconds, and the time for the second train to cross 150m would be 150m / 45km/hr = 3.33 seconds.
To convert kilometers per hour (km/hr) to meters per second (m/s), we need to divide the speed in km/hr by 3.6. Thus, a speed of 40km/hr would be equivalent to 40 / 3.6 = 11.11 m/s, and a speed of 45km/hr would be equivalent to 45 / 3.6 = 12.5 m/s.
The time taken for a train to cross a distance is inversely proportional to its speed. This means that the higher the speed, the shorter the time taken to cover the same distance. In this case, the second train has a higher speed of 45km/hr compared to the first train's speed of 40km/hr. Therefore, it takes less time for the second train to cover a shorter distance of 150m compared to the first train's time to cover 200m.
No, it is not possible for the two trains to cross at the same time. This is because they have different speeds and are covering different distances. The train with a higher speed will always take less time to cross a given distance compared to the train with a lower speed.
The length of the train does not affect the time taken to cross a distance. The time taken is solely dependent on the speed of the train and the distance it needs to cover. The length of the train only affects the distance it needs to cover, but not the time it takes to cross that distance.