Speed of Train B: Solving Physics Homework

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Homework Help Overview

The problem involves two trains moving in opposite directions on parallel tracks, with specific lengths and speeds given. The original poster is tasked with determining the speed of Train B and its velocity relative to Train A, based on the time it takes for the trains to pass each other.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to convert speed from mph to m/s and calculates a value but is uncertain about the next steps. Some participants suggest drawing a diagram and considering velocity addition. Others propose thinking about the implications of the passing time and relative motion.

Discussion Status

Participants are exploring different interpretations of the problem, with some guidance offered regarding relative motion and the perspective of an observer on Train A. There is an ongoing inquiry into the distance covered during the passing time, and a question about the relative velocity remains open.

Contextual Notes

There is a mention of confusion regarding the calculations and the setup of the problem, indicating a need for clarification on the concepts involved in relative motion and velocity addition.

Starsfall
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Homework Statement


Two trains run in opposite directions on parallel tracks. Train A is 30 meters long and runs east to west at 60 mph. Train B is 45 meters long and runs west to east. It takes 0.5 seconds for the trains to pass each other. How fast is train B travelling? What is the velocity of train B relative to train A?

Homework Equations

The Attempt at a Solution


I'm new to physics and lost with this problem. The first thing I did was convert mph to m/s. (60 miles/hour x 1609m/1m x 1 hour/3600s). I got 26.82 m/s but I don't know where to go from there?
 
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Welcome to PF!

I would first try drawing a diagram of the problem and see if you figure it out from there.

You could also assign the other train a velocity of x and think about velocity addition and how it may help you solve it.

Think about what it means for two trains to pass in 0.5 secs as in front to front and end to end.
 
I drew a sketch but that didn't seem to help much. I was thinking maybe 26.82 m/s x 0.5s = 13.02 m/s. I'm just really confused.
 
Starsfall said:
I drew a sketch but that didn't seem to help much. I was thinking maybe 26.82 m/s x 0.5s = 13.02 m/s. I'm just really confused.
It will be simplest to work in terms of relative motion. Consider an observer traveling at the rear of train A. The observer considers A to be stationary, so sees B traveling at the combined speed.
The observer sees the front of train B pass the front of train A, then half a second later the rear of train B pass herself. How far does it appear that train B has moved in that time?
 
haruspex said:
It will be simplest to work in terms of relative motion. Consider an observer traveling at the rear of train A. The observer considers A to be stationary, so sees B traveling at the combined speed.
The observer sees the front of train B pass the front of train A, then half a second later the rear of train B pass herself. How far does it appear that train B has moved in that time?

Would it be 75 meters?
 
r26h said:
Would it be 75 meters?
Yes.
 
r26h said:
Would it be 75 meters?
Can you now answer the second question, the relative velocity?
 

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