Time to Fall 120m: Solving an SUVAT Problem with a Thrown Weight

  • Thread starter Thread starter Rumplestiltskin
  • Start date Start date
  • Tags Tags
    Suvat
Click For Summary
SUMMARY

The discussion centers on solving a SUVAT problem involving the time taken for a weight to fall 120 meters. The correct time for a dropped weight is established as 4.9 seconds using the formula √(s/0.5 x g). When the weight is thrown downwards at an initial velocity of 2.5 m/s, the problem transforms into a quadratic equation: 4.9t² + 2.5t - 120 = 0. The solution to this equation yields a time of 4.7 seconds for the thrown weight.

PREREQUISITES
  • SUVAT equations for motion analysis
  • Quadratic equations and their solutions
  • Understanding of gravitational acceleration (g = 9.8 m/s²)
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the derivation and application of SUVAT equations
  • Practice solving quadratic equations using the Quadratic Formula
  • Explore the effects of initial velocity on free fall problems
  • Learn about gravitational acceleration and its impact on motion
USEFUL FOR

Students studying physics, educators teaching kinematics, and anyone interested in solving motion-related problems using SUVAT equations.

Rumplestiltskin
Messages
97
Reaction score
3

Homework Statement


a) How much time does a dropped weight take to fall 120m down a cliff? (I answered this correctly as 4.9s -- √(s/0.5 x g).)
b) What would the time be (in question a) if the weight was thrown downwards at 2.5m/s?

Homework Equations


SUVAT

The Attempt at a Solution


None, apart from a mistaken rearrangement of s = ut + 0.5at^2.
 
Physics news on Phys.org
I am not familiar with SUVAT, could you provide more detail?
In your equation S = Ut+ .5At^2, the only thing that changes from your first problem is that now u is not 0.
You will end up with a quadratic equation for t. Pick the positive solution.
 
RUber said:
I am not familiar with SUVAT, could you provide more detail?
In your equation S = Ut+ .5At^2, the only thing that changes from your first problem is that now u is not 0.
You will end up with a quadratic equation for t. Pick the positive solution.

How would I isolate t?
 
Rumplestiltskin said:
How would I isolate t?
Have you ever solved a quadratic equation?
 
SteamKing said:
Have you ever solved a quadratic equation?

My bad, I was trying to rearrange for t. This crossroad is new to me.

120 = 2.5t + 4.9t^2
4.9t^2 + 2.5t - 120 = 0

A quadratic formula later... 4.7s. Correct! Thanks all.
 
  • Like
Likes   Reactions: CWatters and RUber

Similar threads

  • · Replies 21 ·
Replies
21
Views
9K
  • · Replies 13 ·
Replies
13
Views
17K
Replies
2
Views
4K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 6 ·
Replies
6
Views
4K
Replies
1
Views
2K
  • · Replies 11 ·
Replies
11
Views
7K
  • · Replies 2 ·
Replies
2
Views
1K