Time to Fall 120m: Solving an SUVAT Problem with a Thrown Weight

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Homework Help Overview

The discussion revolves around a physics problem involving the time it takes for a weight to fall 120 meters, specifically using the SUVAT equations. The original poster presents two scenarios: one where the weight is dropped and another where it is thrown downwards with an initial velocity.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of the SUVAT equations, particularly focusing on the rearrangement of the equation s = ut + 0.5at². Questions arise about isolating the variable t and the implications of having a non-zero initial velocity.

Discussion Status

There is an ongoing exploration of how to solve the quadratic equation that arises from the problem setup. Some participants have offered guidance on using the quadratic formula, while others are clarifying the steps involved in solving for t.

Contextual Notes

Participants express varying levels of familiarity with the SUVAT equations and quadratic equations, indicating a range of understanding within the discussion. The original poster acknowledges a mistake in their initial approach, which has led to further inquiry and clarification among participants.

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Homework Statement


a) How much time does a dropped weight take to fall 120m down a cliff? (I answered this correctly as 4.9s -- √(s/0.5 x g).)
b) What would the time be (in question a) if the weight was thrown downwards at 2.5m/s?

Homework Equations


SUVAT

The Attempt at a Solution


None, apart from a mistaken rearrangement of s = ut + 0.5at^2.
 
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I am not familiar with SUVAT, could you provide more detail?
In your equation S = Ut+ .5At^2, the only thing that changes from your first problem is that now u is not 0.
You will end up with a quadratic equation for t. Pick the positive solution.
 
RUber said:
I am not familiar with SUVAT, could you provide more detail?
In your equation S = Ut+ .5At^2, the only thing that changes from your first problem is that now u is not 0.
You will end up with a quadratic equation for t. Pick the positive solution.

How would I isolate t?
 
Rumplestiltskin said:
How would I isolate t?
Have you ever solved a quadratic equation?
 
SteamKing said:
Have you ever solved a quadratic equation?

My bad, I was trying to rearrange for t. This crossroad is new to me.

120 = 2.5t + 4.9t^2
4.9t^2 + 2.5t - 120 = 0

A quadratic formula later... 4.7s. Correct! Thanks all.
 
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