Time to learn and understand my mistakes.

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Homework Help Overview

The discussion revolves around a problem in electrostatics involving a spherical insulator with charge +Q and a particle with charge -Q located at a distance of 2R from the center of the insulator. The original poster seeks to determine the speed of the particle as it impacts the surface of the insulator.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the integration limits for calculating work done by the electric force, questioning whether to integrate from infinity or between the two specified distances (2R to R). Some suggest using energy conservation principles instead of direct integration.

Discussion Status

There is an ongoing exploration of different methods to approach the problem, with participants providing guidance on the correct application of integration limits and energy conservation. Multiple interpretations of the problem setup are being considered, and participants are actively questioning their assumptions and reasoning.

Contextual Notes

Some participants express confusion regarding the conventions of potential energy and the implications of positive and negative charges in the context of the problem. There is also mention of the original poster's exam context, which may influence the discussion dynamics.

  • #31
But the object isn't in space...it's in the sky. Which is less than the Earth's Radius.
 
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  • #32
flyingpig said:
But the object isn't in space...it's in the sky. Which is less than the Earth's Radius.
Note that the distance 'r' in the Newton formula for gravity is the distance from the object to the center of the earth. For something above the Earth's surface, that distance will be greater than the Earth's radius.
 
  • #33
But the Earth's surface is the sky and the object can't always be higher than the sky
 
  • #34
flyingpig said:
But the Earth's surface is the sky and the object can't always be higher than the sky
The Earth's surface is below the sky.
 
  • #35
Then what is the real radius of the earth?
 

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