Titration - Calculating the endpoint

[future_vet]

Hello,

I have titrated 25 ml of NaOH with 25 ml of HCl. Both are 0.1M.
I need to calculate the expected endpoint for the titration of the strong base with the strong acid.

I know that:
0.025 L x 0.1M = 2.5 x 10^-3 moles of NaOH and HCl each.
I know that I need the same volume of both to do the titration.

But what I don't understand is: how do I calculate the endpoint? What is it supposed to be, a mole amount, a M amount, a volume, a pH?...

Thank you,

J.

 

[Borek]

Question is ambiguous for me. You are asked either about volume of titrant or about pH.

 

[future_vet]

That's what I thought too...

So, if it is the volume of titrant, since the 2 chemicals have the same molarity, the volume of the initial solution would be equal to the volume of the titrant. So, if they ask for the volume, I can do it.

What if I have to calculate the pH at the endpoint? I know how to predict whether it will be above at or below 7.0 depending on what we start with and what the titrant is, but I am not sure what the formula is to find the exact pH...

Any idea?

Thank you!

 

[Stevedye56]

Is this an actuall reaction you are doing or just on paper? In the past all titrations I've done have been volume based.

 

[Borek]

Acid/base titration curve calculation. Don't worry about the beginning (description of the general approach). Scroll to read the text below the equations.