To prove that a field is complex

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The discussion centers on the properties of fields, particularly regarding ordered and complex fields. It clarifies that not all non-ordered fields are complex, citing finite fields and non-real extensions of rational numbers as examples. To prove a field is not ordered, one can check if -1 can be expressed as a sum of squares. The conversation also emphasizes that fields have specific axioms governing addition and multiplication, which must be adhered to for the structure to be valid. Understanding these properties is essential for grasping the nature of fields in mathematics.
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I understand that the complex numbers form a "field" since the complex numbers are closed under addition, subtraction, multiplication, and division. And I understand the complex numbers are not an ordered field since it's not possible to define a relation z1<z2.

My question is: Are all not ordered fields necessarily complex? Then how would you prove that a field is not ordered, is that something that is observed in a system or imposed? Thanks.
 
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Take F={0,1} with

0+0=1+1=0,~1+0=0+1=1

and

0*0=1*0=0*1=0,~1*1=1

then F is a field that can not be ordered.
 
friend said:
I understand that the complex numbers form a "field" since the complex numbers are closed under addition, subtraction, multiplication, and division. And I understand the complex numbers are not an ordered field since it's not possible to define a relation z1<z2.

My question is: Are all not ordered fields necessarily complex?


No. Any finite field is not orderable (in fact, any field of positive characteristic is not ordered), or any non-real extension of \,\mathbb{Q}\, is not orderable...


Then how would you prove that a field is not ordered, is that something that is observed in a system or imposed? Thanks.


A field can be ordered iff -1 can't be expressed as a sum of squares, or equivalently iff a sum of squares equals zero iff every summand is zero.

DonAntonio
 
micromass said:
Take F={0,1} with

0+0=1+1=0,~1+0=0+1=1

and

0*0=1*0=0*1=0,~1*1=1

then F is a field that can not be ordered.

This seems like a very strange way to define + and *. Are you saying that in a field that we can define + and * and way we wish? Or is there some requirements for + and * so that they are consistent with each other?
 
friend said:
Are you saying that in a field that we can define + and * and way we wish?

A field is a specific algebraic structure with its own axioms so, no, we can't do anything we wish. What Micromass described is a special (very small) field.

http://en.wikipedia.org/wiki/Field_(mathematics )

I would suggest doing a little reading on Groups and Rings as well, to give Fields some context. Wikipedia might not be the best place for a beginner to start. Try a free textbook like this:

http://abstract.ups.edu/
 
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friend said:
This seems like a very strange way to define + and *.
It's not that strange at all. It's just like a clock with only two hours: 0 and 1. Take a look at this article: http://en.wikipedia.org/wiki/Modular_arithmetic

Are you saying that in a field that we can define + and * and way we wish? Or is there some requirements for + and * so that they are consistent with each other?

No, there are axioms that + and * must satisfy in order for (F, +, *) to be considered a field. Briefly, (F, +) must be an abelian group, ##(F^\times, *)## must be an abelian group and the distributive law must hold. You can read the axioms in more detail here: http://en.wikipedia.org/wiki/Field_(mathematics).
 
I am studying the mathematical formalism behind non-commutative geometry approach to quantum gravity. I was reading about Hopf algebras and their Drinfeld twist with a specific example of the Moyal-Weyl twist defined as F=exp(-iλ/2θ^(μν)∂_μ⊗∂_ν) where λ is a constant parametar and θ antisymmetric constant tensor. {∂_μ} is the basis of the tangent vector space over the underlying spacetime Now, from my understanding the enveloping algebra which appears in the definition of the Hopf algebra...

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