Torque and angular acceleration of two discs

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SUMMARY

The discussion focuses on the torque and angular acceleration of two fixed disks in a physics problem. The key equations utilized are Ʃτ = Iα and ƩF = ma. It is established that both disks share the same angular acceleration due to being fixed together. The participant correctly identifies the need to analyze tensions in the context of acceleration, clarifying that tensions should be evaluated using free-body diagrams rather than assumptions.

PREREQUISITES
  • Understanding of torque and angular acceleration concepts
  • Familiarity with the moment of inertia (I) in rotational dynamics
  • Knowledge of free-body diagrams for analyzing forces
  • Basic grasp of Newton's second law (ƩF = ma)
NEXT STEPS
  • Study the application of free-body diagrams in rotational systems
  • Learn about moment of inertia calculations for composite objects
  • Explore the relationship between linear acceleration and angular acceleration (a = αR)
  • Investigate tension forces in systems with multiple connected objects
USEFUL FOR

Students studying physics, particularly those focusing on rotational dynamics and torque analysis, as well as educators seeking to clarify these concepts in a classroom setting.

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Homework Statement



2nv7d7a.jpg


Homework Equations



Ʃ[itex]\tau[/itex] = I[itex]\alpha[/itex]
ƩF = ma

The Attempt at a Solution



I was able to calculate A and B which I am confident is correct..

2r5dd1x.jpg


for part C is what I'm having trouble with. Since both disks are fixed together, does that mean they share the same angular acceleration? if so I think the way to go about this is I apply the equation

Ʃ[itex]\tau[/itex] = I[itex]\alpha[/itex]

where it will be T1R1 - T2R2 = I[itex]\alpha[/itex] and I just solve for alpha.

but since they are now accelerating.. doesn't that change each tension to be t = mg + ma? instead of just t = mg ? which then makes it much more difficult to solve..

unless if the tensions are just mg then it will be fairly easy to solve since I can find the alpha of the rotating system then just apply the equation

a = [itex]\alpha[/itex]R

and calculate the a for each, and from there I will be able to find the tensions in each rope.
 
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Since both disks are fixed together, does that mean they share the same angular acceleration?
Yes - that is what "fixed together" means. You needed to assume this to do (a) and (b).

since they are now accelerating.. doesn't that change each tension to be t = mg + ma?
Use the free-body diagram to inform you of the tensions. Don't anticipate.
 

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