Torque direction using right hand rule

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The discussion revolves around determining the direction of torque exerted by tension T1 in a given scenario. The right-hand rule is applied, with the conclusion that torque is positive if counterclockwise is defined as positive. It is noted that the designation of torque as positive or negative is dependent on the chosen coordinate axes. Additionally, the torque direction is confirmed to point towards the observer. Ultimately, the classification of torque as positive or negative lacks meaning without a defined axis.
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Homework Statement


I am confused on the drawing below, is the direction of the torque exerted by tension T1 positive or negative?

http://img444.imageshack.us/img444/5190/katrolrh3.jpg
http://g.imageshack.us/img444/katrolrh3.jpg/1/

Homework Equations





The Attempt at a Solution



I'd say it's positive, as using the right hand rule.. my thumb points towards me... is this right?
 
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I think that would be correct if you were saying that the counterclockwise direction is positive. That would make T2 negative, if that makes sense.
 
Since the torque is a vector, whether it is "positive" or "negative" depends on how you choose your axis. You are right, the torque points towards you. Asking whether this is positive or negative, without knowing the coordinate axes, is meaningless.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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