A 2.0-kg block starts from rest on the positive x axis 3.0 m from the origina and thereafter has an acceleration given by a = 4i-3j. The torque, relative to the origin acting on it at the end of 2.0 s is:
linear acceleration= (radius)(angular acceleration)
torque= (moment of Inertia)(angular acceleration)
The Attempt at a Solution
I found the angular acceleration using the formula above
moment of Inertia=(mass)(radius square)
Then find the torque using the formula above
that's not it....help!...