Torque on a block with acceleration 4i-3j.

  • Thread starter chouZ
  • Start date
  • #1
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Homework Statement


A 2.0-kg block starts from rest on the positive x axis 3.0 m from the origina and thereafter has an acceleration given by a = 4i-3j. The torque, relative to the origin acting on it at the end of 2.0 s is:


Homework Equations



linear acceleration= (radius)(angular acceleration)

torque= (moment of Inertia)(angular acceleration)

The Attempt at a Solution



I found the angular acceleration using the formula above
moment of Inertia=(mass)(radius square)
Then find the torque using the formula above

that's not it....help!...:frown:
 

Answers and Replies

  • #2
Hootenanny
Staff Emeritus
Science Advisor
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HINT: Definition of torque;

[tex]\tau = \vec{F}\times \vec{r} = m\vec{a}\times\vec{r}[/tex]
 
  • #3
Doc Al
Mentor
45,031
1,330
Hint: Where is the block at the end of 2 seconds?
 
  • #4
11
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thanks for the help guys...
 

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