Torque on a Free Body: Applying 1N Force to Ruler

Click For Summary
SUMMARY

The discussion focuses on the application of a 1N force to a 10cm, 0.01kg ruler in space and the resulting dynamics. Two primary methods for analyzing the torque and motion are presented: using the point of force application as the pivot, which simplifies torque calculations, and using the center of mass as the pivot, which allows for separate calculations of linear motion and torque. Both methods yield consistent results, emphasizing the importance of analyzing both linear and rotational dynamics in this scenario.

PREREQUISITES
  • Understanding of Newton's Second Law (F=ma)
  • Familiarity with concepts of torque and moment of inertia
  • Knowledge of linear and angular momentum
  • Basic principles of rotational dynamics
NEXT STEPS
  • Study the calculation of torque in rigid body dynamics
  • Learn about moment of inertia for different shapes and axes
  • Explore the relationship between linear and angular momentum
  • Investigate the effects of applying forces at various points on an object
USEFUL FOR

Physics students, mechanical engineers, and anyone interested in understanding the dynamics of forces and torques in rigid bodies.

tomz
Messages
35
Reaction score
0
Hi everyone, I have a very simple and classic question here.

Suppose I have a 10cm,0.01kg ruler (uniform density) in space. And I apply a 1N force 2 cm from the left end of it. What happened at this instance? I guess centre of the ruler will start to accelerate as a=F/m=100ms^2. But what about the torque? which point should I consider as the pivot position. (Here I want what happen at the very first instance only). Is it the centre of mass? If it yes, why??

Thank you for answering!
 
Physics news on Phys.org
You can choose any axis you like. They will all work.

There are two choices that are attractive at first glance

1. Consider the point of application of your force as the axis of rotation.

This has the advantage that your force exerts no torque. You can now compute the linear motion of the ruler's center-of-mass (100 m/s^2 as before), compute how much angular momentum that represents, compute the moment of inertia of the ruler about this axis and deduce a rotational acceleration rate that keeps total angular momentum
constant.

2. Consider the center of mass as the axis of rotation.

This has the advantage that the linear motion of the ruler does not contribute to total angular momentum. You can now compute the linear motion of the ruler based on the force applied and separately compute the torque and moment of inertia of the ruler about its center and deduce a rotational acceleration rate based on that.

You should perform both calculations and assure yourself that the results match.

With any other axis you can cancel neither the torque applied by the forst nor the angular momentum contributed by the linear acceleration of the center-of-mass. Analysis is still possible but is somewhat more difficult. It will still produce the same result.

Two additional attractive choices are the two ends of the ruler (making it slightly easier to determine its moment of inertia).
 
Last edited:

Similar threads

  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
10
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K