The circular blade on a radial arm saw is turning at 262 rad/s at the instant the motor is turned off. In 18.0 s the speed of the blade is reduced to 85 rad/s. Assume the blade to be a uniform solid disk of radius 0.130 m and mass 0.400 kg. Find the net torque applied to the blade.
Sum torque=moment of inertia X angular deceleration
The Attempt at a Solution
=.5*.4(.13)^2*10 = .0338 Nm