Torque required to rotate an object at an angle

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To calculate the torque required to rotate a platform initially at a declined angle, one must consider the load's position and the angle of rotation. The torque is zero at both 0 and 180 degrees, peaking at 90 degrees due to the opposing torque created by the load. The torque can be determined using the formula involving the load's force and the sine of the angle, multiplied by the distance from the load to the axis of rotation. The choice of slew ring will influence the final torque requirement, as it facilitates the circular movement. Understanding the forces involved is crucial for accurately resolving the torque needed at the drive motor.
jhogue74
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I am trying to work out the torque required to rotate a platform, initially declined at an angle. See attached hand sketch.
My situation is
- I have a platform initially at a declined angle, say at 0 degrees.
- I have a load at the end of the platform at 0 degrees
- I want to be able to rotate the platform and load 180 degrees from its initial position
- I am ignoring the platform self weight at the moment for simplicity

My thoughts are that the torque required is related to the amount of work required to lift the load F from point 1 to point 2, for now ignoring efficiencies of components etc. The final torque required will be based on the slew ring I choose to allow the circular movement.

Could anyone give me their thoughts on my situation. Trying to work my way through what loads/forces are to be considered and then resolving this back to a torque at the drive motor.

Thanks,

Jason
 

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Hello jhogue, ##\quad## :welcome: ##\quad## !

torque in your scenario depends on how far the platform has rotated: it's 0 at 0 and 180 degrees and maximum at 90.

At that point you have an opposing torque ##\ F\sin(85) \ ## times the distance between load and axis.

I don't understand what a slew ring is or what it is supposed to do.
 
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