Torque required to tilt 1200 kg mass?

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SUMMARY

The discussion focuses on calculating the torque required to tilt a 1200 kg mass, specifically a 1200mm diameter cylinder with a height of 2.5 meters. The tilting point is located at the corner of an "L" shaped platform, and the shaft diameter for tilting is 63mm. The angular acceleration is specified as 0.05236 rad/sec², and the goal is to determine the necessary torque for selecting an appropriate worm reduction gearbox and motor for operation.

PREREQUISITES
  • Understanding of torque calculations in mechanical systems
  • Familiarity with angular acceleration concepts
  • Knowledge of worm reduction gearboxes and their specifications
  • Basic principles of rotational dynamics
NEXT STEPS
  • Calculate the torque using the formula: Torque = Moment of Inertia x Angular Acceleration
  • Research specifications for worm reduction gearboxes suitable for 1200 kg loads
  • Explore motor selection criteria based on torque requirements
  • Investigate the effects of different shaft diameters on torque transmission
USEFUL FOR

Mechanical engineers, designers of lifting systems, and anyone involved in selecting motors and gearboxes for heavy machinery applications.

Mohit Patil
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Object to be tilted = 1200mm diameter cylinder
Cylinder height = 2.5 meter
weight of tilting assembly = 1200 kg
Cylinder is on platform which is "L" shaped and tilting point is on that corner of "L" as in attached image.
Shaft diameter on which it is tilted id 63mm
Angular acceleration = 0.05236 rad/sec^2

tilting angle 90 degree
I need to calculate torque so that i can select worm reduction gearbox and motor required for operation.
(Attached image for reference)
 

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