Torque Units: Help Understanding kg force cm

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SUMMARY

The discussion focuses on understanding the torque unit "kilogram force centimeter" (kg force cm) and its application in lifting weight. It is established that 3.6 kg force cm equates to 0.35 Nm of torque, which can be utilized with different pulley radii to lift varying weights. For instance, using a 4.0 m pulley allows lifting 0.088 N, while a 0.12 m pulley enables lifting 2.9 N. The relationship between torque, force, and moment arm is crucial for practical applications in mechanics.

PREREQUISITES
  • Understanding of torque and its calculation (Torque = Force x Moment Arm)
  • Basic knowledge of Newton's laws of motion
  • Familiarity with unit conversions (e.g., kg force to Newtons)
  • Concept of pulleys and their mechanical advantage
NEXT STEPS
  • Learn about torque calculations in different units (e.g., Nm, kg force cm)
  • Explore the principles of mechanical advantage in pulley systems
  • Study the relationship between power, torque, and RPM in motors
  • Investigate real-world applications of torque in automotive engineering
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Engineers, mechanics, and physics students who seek to deepen their understanding of torque measurements and their practical implications in lifting and mechanical systems.

ramonegumpert
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Dear Physics Gurus, o:)

I am trying very hard to understanding the units used to measure torque.

I know there is a unit called kilogram force centimeter, and 1 ounce force inch = 0.072007790632 kg force cm.

My problem is I do not understand what these units mean. I could only find definition for Kilogram-force and not Kilogram-force-cm.
for example: http://en.wikipedia.org/wiki/Kilogram-force

How much weight can a motor lift if it is rated 3.6 kg force cm and also rated at 200 rpm? Does it mean it can lift a maximum of 3.6 kg at a speed of 200 rpm? And how many centimeters will it lift per minute?

As you can see, i am kinda confused :confused: and cannot 'feel' how much weight can be lifted given the torque unit of kg force cm.

Please could you help me.

Best regards
Ramone
 
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Torque = Force x moment arm
In your case, consider 3.6 kg force with a 1.0 cm moment arm (you could use any combination - I picked this one only to make it easy).
3.6 kg force = 35 N
1.0 cm = 0.01 m
So, you have 0.35 Nm of torque.
How you use that torque is up to you. You can now use a pulley with r = 4.0 m and you can lift 0.35 Nm/4.0 m = 0.088 N, or you can use a pulley with r = 0.12 m and you can lift 0.35 Nm/0.12 m = 2.9 N. The difference will be the velocity with which you can lift.
 
Here is a sample of how to use torque in Newton meters (Nm) on your car engine

Power (watts) = torque (Nm) x RPM x 2 pi/60
Horsepwer = watts/746

Example 100 Nm torque and 2200 RPM = 23,038 watts = 30.9 HP
 
TVP45 said:
Torque = Force x moment arm
In your case, consider 3.6 kg force with a 1.0 cm moment arm (you could use any combination - I picked this one only to make it easy).
3.6 kg force = 35 N
1.0 cm = 0.01 m
So, you have 0.35 Nm of torque.
How you use that torque is up to you. You can now use a pulley with r = 4.0 m and you can lift 0.35 Nm/4.0 m = 0.088 N, or you can use a pulley with r = 0.12 m and you can lift 0.35 Nm/0.12 m = 2.9 N. The difference will be the velocity with which you can lift.

Dear TVP45,
Thank you very much for your explanation which has fully clarified my doubt. I am very greatful.

Thanks also to Bob S for the useful example.

Cheers!

Best regards
Ramone
 

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