Torsion constant of a bent spring

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SUMMARY

The torsion constant (K_t) of a bent spring can be calculated using the formula K_t = T/θ = F/x * r^2, where K represents the linear stiffness, F is the force applied, x is the angular displacement, and r is the distance from the spring to the center of rotation. The discussion confirms that bending the spring does not inherently change its torsional stiffness unless the deformation restricts the spring's ability to rotate freely. In extreme cases of bending, the spring may behave as two independent springs, effectively doubling the torsional stiffness. However, the initial deformation reduces the torsional stress limit the spring can withstand.

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Piyush Hatwalne
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How do I find torsion constant (Kt) of a spring which is bent, as shown in the image below
 

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K_t= \frac{T}{\theta}= \frac{Fr}{\frac{x}{r}}= \frac{F}{x}r^2= Kr^2

Where K is the linear stiffness of the spring and r is the distance between the spring and the center of rotation.
 
Hello,
May be I wasn't clear in previous post. The spring is being rotated along its axis, while being kept in a curved position. In this case how will the torsion constant change ?
 
Sorry about that.

I'm going to let other chimes in, but I don't think it change anything for the torsional stiffness; Just like the bent doesn't change anything to linear stiffness (for example, the way I thought you were using the spring). The torsional stiffness is:

Torsion_spring_2.gif


and none of these variables should change if the spring is bent. The exception would be if the bent deformed the spring so much that it doesn't allow the spring to freely rotate. For example, if the bent is so pronounced that it looks like 2 springs side by side joint by a wire, you will probably end up with 2 independent springs with half the active coils of the initial spring (i.e. twice the initial spring torsional stiffness).

However, because there is an initial deformation, the torsional stress limit that it can withstand will be lower.
 

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