Tossing upward with air resistance

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SUMMARY

The discussion centers on calculating the distance an object travels when tossed upward while accounting for air resistance. The correct approach involves using the kinematic equation vf² = vi² + 2ad, where "a" represents the net acceleration due to gravity and drag force. Participants emphasize the importance of applying Newton's Second Law to derive the effective acceleration, which includes both gravitational and drag forces. Misinterpretations of the equation's components, particularly regarding the force of friction from air resistance, are clarified.

PREREQUISITES
  • Understanding of kinematic equations, specifically vf² = vi² + 2ad
  • Familiarity with Newton's Second Law of Motion
  • Knowledge of drag force and its calculation
  • Basic principles of physics related to motion and forces
NEXT STEPS
  • Study the derivation of drag force equations in fluid dynamics
  • Learn how to apply Newton's Second Law to systems with multiple forces
  • Explore advanced kinematic equations that incorporate air resistance
  • Investigate numerical methods for solving motion equations with variable forces
USEFUL FOR

Physics students, educators, and anyone interested in understanding motion dynamics involving air resistance and forces.

jvileisis
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Could someone tell me if my approch to this is correct? I am given the change in vertical v final(zero), v initial, mass, and frictional coefficient. The question askes for distance. I set up the equation vf^2=vi^2+2ad(mg(frictional coefficient))
 
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I don't understand what you mean by that equation. If you are multiplying the 2ad term by the force of friction from the air then you are incorrect.

That kinematic equation is still valid in its normal form. The difference is that "a" will not be the acceleration caused by gravity, but it will be the acceleration caused by the sum of gravity and the drag force.

HINT: Can you find this acceleration starting from Newton's Second Law?
 

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