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Tossing upward with air resistance

  1. Dec 16, 2007 #1
    Could someone tell me if my approch to this is correct? I am given the change in vertical v final(zero), v initial, mass, and frictional coefficient. The question askes for distance. I set up the equation vf^2=vi^2+2ad(mg(frictional coefficent))
  2. jcsd
  3. Dec 16, 2007 #2


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    I don't understand what you mean by that equation. If you are multiplying the 2ad term by the force of friction from the air then you are incorrect.

    That kinematic equation is still valid in its normal form. The difference is that "a" will not be the acceleration caused by gravity, but it will be the acceleration caused by the sum of gravity and the drag force.

    HINT: Can you find this acceleration starting from Newton's Second Law?
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