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**1. Homework Statement**

A car is driven east for a distance of 48 km, then north for 26 km, and then in a direction 30° east of north for 28 km. Draw the vector diagram and determine the total displacement of the car from its starting point and its direction.

**2. Homework Equations**

im not sure.. if i tackle this problem right...

x=rcos

y=rsin

arctan(y/x)= teta

**3. The Attempt at a Solution**

I try to find the displacement from (48,26) then add to the (28cos30),(28sin30) which give the final destination point in Cartesian Coordinate.. then i use the distance formula.. but it keep giving me a different answer..

so i got (48+28cos30),(26+28sin30)

then sqrt((48+28cos30)^{2}+(26+28sin30)^{2}) = displacement.. i keep getting 82.5 but the answer is 79.8

and then i use the coordinate to find the dirrection.. but my calc keep giving me 29 degree.. answer is 39