Total energy oscillation problem

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SUMMARY

The total energy oscillation problem involves a mass of 0.01 kg with a displacement function defined as x(t) = 0.25m sin(62.83t/s − 0.785398). The amplitude is determined to be 0.25 m. The speed at t = 0 is calculated using the derivative of the displacement function, yielding v(0) = 0.25m * 62.83 * cos(-0.785398). The total energy is expressed as the sum of kinetic energy (KE) and potential energy (PE), with the formula Total energy = (1/2)kA² being relevant for further calculations.

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  • Understanding of harmonic motion and oscillation principles
  • Familiarity with calculus, specifically derivatives
  • Knowledge of energy conservation in mechanical systems
  • Proficiency in trigonometric functions and their applications in physics
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  • Calculate the spring constant k using the relationship between total energy and amplitude
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Homework Statement



The displacement of a mass m = 0.01 kg is x(t) = 0.25m sin(62.83t/s − 0.785398) Find its amplitude, its total
energy, and its speed at t = 0.



Homework Equations



E = Av^2 + Bx^2
x = Asin(wt-theta)


The Attempt at a Solution



i use that above formula to find that Amplitude = .25
speed at t = 0 should be the derivative of the x function i think

v(t) = (.25m)(62.83)cos(62.83t/s - 0.785398)
v(0) = (.25m)(62.83)cos(- 0.785398)

I am not sure about the last part there with finding the energy, any suggestions?
 
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Total energy = KE + PE

Total energy = (1/2)kA2
 

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