Total Energy Problem: Ratio of A to B

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SUMMARY

The discussion focuses on calculating the ratio of total energy of a 2.00 kg object at two positions: A (20.0 m above ground) and B (8.00 m below A). The gravitational acceleration is given as g = 10.0 m/s². The total mechanical energy at position A consists solely of gravitational potential energy, while at position B, it includes both potential and kinetic energy depending on the object's motion. The key takeaway is that the ratio of total energy at A to total energy at B is determined by the object's state of motion when transitioning between the two points.

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  • Understanding of gravitational potential energy calculations
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  • Familiarity with the conservation of mechanical energy principle
  • Basic algebra for ratio calculations
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Homework Statement



An object of mass 2.00 kg is held at a position A, a vertical height of 20.0 m above the ground. Point B is 8.00 m directly below A. Neglect air resistance and use g=10.0 m/s(squared)

What is the ratio of the total energy of the object at position A to position B?

Homework Equations



g=10.0 m/s(squared)

The Attempt at a Solution

 
Last edited:
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What is the difference in energy between the object at rest at position A and the object at rest at position B? (There's another equation you need, and you must have just seen it if you've been assigned this problem.)
 
By the way - did you quote the problem exactly? I ask because it doesn't actually state how the object gets from A to B. If it's just dropped and is moving when it passes B, that's different than if you just lower it to B and let it come to rest there.
 

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