Calculating Total Flight Time for a Rocket: A Scientific Approach

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SUMMARY

The total flight time for the rocket was calculated incorrectly. The initial velocity at ground level is 80.2 m/s, and the rocket reaches a maximum altitude of 1,080 m with an acceleration of 3.80 m/s². The time to reach this maximum altitude is 23.0823 seconds. The correct calculation for the total flight time must include the time of free fall from the maximum altitude, which requires determining the velocity at that altitude and the subsequent time to impact.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Familiarity with concepts of velocity, acceleration, and free fall
  • Knowledge of gravitational acceleration (9.80 m/s²)
  • Ability to perform calculations involving initial and final velocities
NEXT STEPS
  • Calculate the velocity of the rocket at maximum altitude using kinematic equations
  • Determine the time of free fall from maximum altitude to ground impact
  • Review the principles of projectile motion and free fall
  • Explore the effects of varying acceleration on flight time calculations
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Aerospace engineers, physics students, and anyone interested in rocket flight dynamics and kinematic calculations.

ColeridgianHam
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Homework Statement
A missile silo is used to launch interplanetary rockets vertically upward out of the silo, giving the rocket an initial speed of 80.2 m/s at ground level. As the rocket clears the silo, the engines fire, and the rocket accelerates upward at 3.80 m/s^2 until it reaches an altitude of 1,080 m. At that point its engines fail, and the rocket goes into free fall, with an acceleration of −9.80 m/s^2.
Determine the rocket's velocity (in m/s) just before ground impact and its total time of flight (in s).
Relevant Equations
t=(Vx-Vi)/a
I calculated the time for the velocity before ground impact, which is v = -189.23 and the velocity at end of engine burn time, which is 120.996. I also calculated the max altitude (y = 1826.94), and the time to reach the max altitude was t = 23.0823 seconds. So from this information, I did:
t = (-189.23 + 120.996)/-9.80 = 6.9626 seconds.
Since the question asked for total flight time, I added this time together with the time to reach the maximum altitude:
6.9626s + 23.0823s = 30.0449 seconds
However, I was told my calculation for the total flight time is wrong, while everything else is correct. Where did I mess up?
 
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The rocket has initial velocity 80.2 m/s at groud level when t=0 s and go up to 1080 m with acceleration 3.80 m/s^2. When , say t1, the rocket reached height 1,080 m ?. How much speed, say v1, does it have then?

The rocket free falls with initial velocity v1 with gravity g downward at t=t1 second. When, say t2, the rocket crash to ground ? How much speed, say v2, does it have then?
 
ColeridgianHam said:
t = (-189.23 + 120.996)/-9.80 = 6.9626 seconds.
Since the question asked for total flight time, I added this time together with the time to reach the maximum altitude:
But t is not the time to fall from max altitude. What is the velocity at max altitude?
 
ColeridgianHam said:
t = (-189.23 + 120.996)/-9.80 = 6.9626 seconds.
This figure is supposed to have been the time taken for the Earth's gravity to reverse a 120.996 meter per second upward velocity into a -189.23 meter per second downward velocity.

Can you see a sign error in the calculation?
 
mjc123 said:
But t is not the time to fall from max altitude. What is the velocity at max altitude?
Your point is valid, but having corrected the calculation of that t (per post #4) it would be simpler to consider what time should be added to it to get the total flight time.
 

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