- #1
jsalapide
- 39
- 0
If the transparent material has an index of refraction of 1.2, what is the angle of incidence beyond which total internal reflection occurs?
Total Internal Reflection in Refraction Physics: Solving for Critical Angle
- Thread starter jsalapide
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- Physics Refraction
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Homework Help Overview
The discussion revolves around the concept of total internal reflection in the context of refraction physics, specifically focusing on calculating the critical angle for a transparent material with a given index of refraction.
Discussion Character
- Conceptual clarification, Mathematical reasoning
Approaches and Questions Raised
- Participants discuss the calculation of the critical angle using Snell's Law and question the interpretation of the result, particularly regarding the conditions for total internal reflection.
Discussion Status
There are multiple interpretations being explored regarding the critical angle, with some participants confirming their calculations while others seek clarification on how to express the conditions for total internal reflection.
Contextual Notes
One participant notes the need to show work on the problem to receive further assistance, indicating a potential homework guideline in place.
- #2
jsalapide
- 39
- 0
I solved for the critical angle and I got 56.44 degrees,
Should the answer be "greater than 56.44 degrees" so that the total internal reflection may occur?
- #3
- 12,179
- 186
EDIT: this is in response to post #1.
You'll have to show some work on the problem before receiving help.
Snell's Law is helpful here. You could also review your textbook or lecture notes discussion of total internal reflection.
Last edited:
- #4
- 12,179
- 186
Correctjsalapide said:
Since they are asking for the angle beyond which total internal reflection occurs, the answer is simply 56 degrees.
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