- #1
jsalapide
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If the transparent material has an index of refraction of 1.2, what is the angle of incidence beyond which total internal reflection occurs?
Total Internal Reflection in Refraction Physics: Solving for Critical Angle
- Thread starter jsalapide
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SUMMARY
The discussion centers on calculating the critical angle for total internal reflection in a transparent material with an index of refraction of 1.2. The critical angle was determined to be 56.44 degrees. For total internal reflection to occur, the angle of incidence must be greater than this critical angle. Participants confirmed that the answer should indeed be "greater than 56.44 degrees" for total internal reflection to take place.
PREREQUISITES- Understanding of Snell's Law
- Familiarity with the concept of index of refraction
- Knowledge of total internal reflection principles
- Basic trigonometry for angle calculations
- Study Snell's Law in detail to understand refraction and critical angles
- Explore the concept of total internal reflection in optical fibers
- Review textbooks or lecture notes on optics for deeper insights
- Practice solving problems related to critical angles and refraction
Students studying physics, particularly those focusing on optics, as well as educators and anyone interested in the principles of light behavior in different media.
- #2
jsalapide
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I solved for the critical angle and I got 56.44 degrees,
Should the answer be "greater than 56.44 degrees" so that the total internal reflection may occur?
- #3
- 12,178
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EDIT: this is in response to post #1.
You'll have to show some work on the problem before receiving help.
Snell's Law is helpful here. You could also review your textbook or lecture notes discussion of total internal reflection.
Last edited:
- #4
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Correctjsalapide said:
Since they are asking for the angle beyond which total internal reflection occurs, the answer is simply 56 degrees.
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