twiztidmxcn
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hey
so I'm doing this question on total internal reflection and have got myself totally lost
here is the question:
what is the smallest angle \theta(1) for which a laser beam will undergo TIR on the hypotenus of this glass prism?
after reflecting off the hypotenuse at \theta(c) the laser exits the prism through the bottom face. does it exit to the right or left of the normal? at what angle?
http://photos-603.facebook.com/n11/161/86/37900227/n37900227_30061603_2132.jpg
that is a picture of what is going on here
Now, i realize that at some point I am going to be using snells law as well as the equation for critical angle. My question is.. what do I do?
I am totally lost as you can probably see, and any help would be much appreciated
thank you
twiztidmxcn
*edit*
i've used the critical angle equation and found that the critical angle is 41.81 degrees (using n1 = 1.5 for glass, n2 = 1.0 for air) and didn't know what to do with it... i ended up subtracting the triangle angle of 30 degrees and setting 1.5*sin11.81 = 1*sin theta and solved for theta. i got the right answer, but am not sure how the 30 degrees is subtracted. i know it involves similar triangles but am just not seeing it i guess.
same for the second part, i just subtracted 60-41.81 and then setup the same equation to find my angle coming out, which again i got correct, but am stumped as to how that works.
so I'm doing this question on total internal reflection and have got myself totally lost
here is the question:
what is the smallest angle \theta(1) for which a laser beam will undergo TIR on the hypotenus of this glass prism?
after reflecting off the hypotenuse at \theta(c) the laser exits the prism through the bottom face. does it exit to the right or left of the normal? at what angle?
http://photos-603.facebook.com/n11/161/86/37900227/n37900227_30061603_2132.jpg
that is a picture of what is going on here
Now, i realize that at some point I am going to be using snells law as well as the equation for critical angle. My question is.. what do I do?
I am totally lost as you can probably see, and any help would be much appreciated
thank you
twiztidmxcn
*edit*
i've used the critical angle equation and found that the critical angle is 41.81 degrees (using n1 = 1.5 for glass, n2 = 1.0 for air) and didn't know what to do with it... i ended up subtracting the triangle angle of 30 degrees and setting 1.5*sin11.81 = 1*sin theta and solved for theta. i got the right answer, but am not sure how the 30 degrees is subtracted. i know it involves similar triangles but am just not seeing it i guess.
same for the second part, i just subtracted 60-41.81 and then setup the same equation to find my angle coming out, which again i got correct, but am stumped as to how that works.
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