- #1
Tiran
- 97
- 36
Based on the Comex Hydra 10 tests, a diver breathing the correct mix can withstand a depth of 2300 ft, or the pressure of a column of water 2300 feet tall - nearly 1000 psi.
Since the diver is buoyant (being the same average density as the water), they are essentially weightless. Not in freefall, but weightless.
Given neutral buoyancy and a "preload" of 1000 psi, is there any reason a person couldn't endure the G force acceleration equivalent of the weight of that 2300 foot water column? In other words, if you put a pilot/astronaut in small vat that is under that high pressure, and then subject that vat to 67 Gs of sustained acceleration, would the pilot even feel it? (1000 psi / 14.7 psi = 67) I understand that the life support system may need to adjust the pressure as G load increases because the water above the pilot will get heavier.
First, does that make any sense? And am I applying the right basic formula in making High G equivalent to high pressure at 14.7 psi = 1G?Thanks!
Since the diver is buoyant (being the same average density as the water), they are essentially weightless. Not in freefall, but weightless.
Given neutral buoyancy and a "preload" of 1000 psi, is there any reason a person couldn't endure the G force acceleration equivalent of the weight of that 2300 foot water column? In other words, if you put a pilot/astronaut in small vat that is under that high pressure, and then subject that vat to 67 Gs of sustained acceleration, would the pilot even feel it? (1000 psi / 14.7 psi = 67) I understand that the life support system may need to adjust the pressure as G load increases because the water above the pilot will get heavier.
First, does that make any sense? And am I applying the right basic formula in making High G equivalent to high pressure at 14.7 psi = 1G?Thanks!