Total time In air for a projectile

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SUMMARY

The total time a springboard diver remains in the air after jumping from a 10-meter tower with an initial vertical velocity of 5 m/s and a horizontal velocity of 2 m/s is determined using kinematic equations. The diver's vertical motion is influenced by gravitational acceleration, necessitating the use of displacement formulas rather than simple velocity calculations. The correct approach involves applying the formula X = Vot + 0.5at², ensuring consistent directionality for all variables. The final calculated time in the air is approximately 2 seconds.

PREREQUISITES
  • Understanding of kinematic equations
  • Knowledge of gravitational acceleration (9.81 m/s²)
  • Familiarity with vector components of motion
  • Ability to apply displacement formulas in physics
NEXT STEPS
  • Study kinematic equations in detail, focusing on vertical motion
  • Learn how to resolve vector components in projectile motion
  • Explore the concept of acceleration due to gravity in free fall
  • Practice solving problems involving displacement and time in projectile motion
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Physics students, educators, and anyone interested in understanding projectile motion and kinematics in real-world scenarios.

bionut
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1. A springboard diver performs a dive from a 10 metre tower and jumps with an initial vertical velocity of 5 ms and horizontal velocity of 2 ms. Determine the time she has in the air to perform her dive?


The Attempt at a Solution



From what I know 0=Vi + at (will give me 1/2 the flight time)
t=5/9.81
t=-0.51 X 2 = Total = 1.02 s... whhich is wrong (do I need to incorperate the Disatnce) or should I try and find the angle between the 2 velocities?
 
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bionut said:
1. A springboard diver performs a dive from a 10 metre tower and jumps with an initial vertical velocity of 5 ms and horizontal velocity of 2 ms. Determine the time she has in the air to perform her dive?


The Attempt at a Solution



From what I know 0=Vi + at (will give me 1/2 the flight time)
t=5/9.81
t=-0.51 X 2 = Total = 1.02 s... whhich is wrong (do I need to incorperate the Disatnce) or should I try and find the angle between the 2 velocities?


You have calculated how long until the diver passes the tower on the way down. She still has to get all the way to the water!
 
would it just be as siple as 10m height @ 5m/s = 2s?
 
bionut said:
would it just be as siple as 10m height @ 5m/s = 2s?

Unfortunately - NO.

The diver will be accelerating all the way down.

If you use one of the displace ment formulae, rather than just the velocity formula, the answer should come out.

Like for example X = Vot + 0.5 a t2

make sure you are consistent with positive and negative.
Decide which direction [up or down] will be positive, and be consistent with the displacement, Initial velocity and acceleration.
 

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