Touque and Work from a Dipole Moment

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Cllzzrd
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Problem:
A dipole consists of charges +q and -q separated by 0.62nm . It is in an electric field 2.6×104 C/N.

What is the work required to rotate the dipole from being oriented parallel to the field to being antiparallel to the field?

Equations:
. 90
w=[tex]\int[/tex](p*E*sin(x)
. 0

t=p*E*sin(x)

Work:

The first part asked for the dipole moment, which i found to be 9.9E-29 C*M

So i calculated the torque to be 2.6E-24 N*M, and the second part was the torque at 45 degrees. I found that this was 1.8E-24 N*M.

The last part asked for the work if it was turned from parallel to the electric field to antiparallel.

so I used the formula above and kept getting 1.47E-24 J. The correct answer was 5.2E-24 and I cannot figure out how to get that answer.

Disclaimer: The only reason I know the correct answer is because I got the wrong answer too many times and so it showed me the right answer. I need to figure out how to do this problem.
 
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Cllzzrd said:
The last part asked for the work if it was turned from parallel to the electric field to antiparallel.

so I used the formula above and kept getting 1.47E-24 J. The correct answer was 5.2E-24 and I cannot figure out how to get that answer.
Why does your formula have the integral from 0 to 90? You are going from parallel to antiparallel.
 
More importantly, why are you wearing a touque while working on this? Are you in Quebec?
 
Doc Al said:
D'oh!

Let's see how long this takes...