- #1

- 365

- 11

I thought that was clever and tried to see if this could work for other operations like multiplication (##x\cdot x\cdot x \cdot\ ...=2##), division (##\frac{x}{\frac{x}{\frac{x}{...}}}=2##), addition (##x+x+x+...=2##) and subtraction(##x-x-x-...=2##), but realized it didn't. Any idea what's special about the exponent operation that allows for this clever "substitution of infinite terms" type of solution?